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Re: [PHP] What's with 2016-11-06




For what it's worth, to modify the code you originally posted, don't calculate:

Replace:  $calday = $calday + (60 * 60 * 24);

With:       $calday = strtotime('+1 day', $calday);

On Tue, Oct 25, 2016 at 9:10 AM, Cliff Nieuwenhuis
<c.nieuwenhuis@xxxxxxxxxxxxxx> wrote:
> This is a stripped-down version of a calendar program.  Can anyone explain why November 6 2016 appears twice? Or 2015-11-01?
>
> I'm assuming the fault lies with
>
>         $calday = $calday + (60 * 60 * 24);
>
> ...but I'd like to know why some days apparently have less than 86400 seconds and how (efficiently) to work around that.
>
> Here is my code:
>
>         $calday = strtotime('2016-10-30');
>         $finish = strtotime('2016-12-01');
>
>         while ( $calday < $finish ) {
>                 for ($dow = 0; $dow < 7; $dow++) {
>
>                         // set the year, month, and day
>                         $year = (int) date('Y', $calday);
>                         $month = (int) date('n', $calday);
>                         $day = (int) date('j', $calday);
>
>                         echo "Year: $year, Month: $month, Day: $day, Day of Week: $dow <br />\n";
>
>                         // move on to the next day
>                         $calday = $calday + (60 * 60 * 24);
>                 }
>                 echo "* * *<br />\n";
>         }
>
> Thanks in advance for any help.
>
> --
> Clifford R. Nieuwenhuis
> IT Manager
> Architectural Design Consultants, Inc.
> c.nieuwenhuis@xxxxxxxxxxxxxx
> 608-254-6181
>
>
> --
>
> Clifford R. Nieuwenhuis
> IT Manager
> Architectural Design Consultants, Inc.
> c.nieuwenhuis@xxxxxxxxxxxxxx
> 608-254-6181
>
> Visit our redesigned website:
> www.adcidesign.com
>
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