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RE: [PHP] is_readable fails with a variable parameter




Also I should mention that I thought that maybe the zip file was not being created in time for this point of my code. But I double checked that that file is there at that point of the code. So again it exists. And if it were the other scenario--permissions--the code would not be able to execute if the file path/name were hard coded. So I'm stumped. 

Date: Tue, 29 Sep 2015 13:00:55 -0400
Subject: Re: [PHP] is_readable fails with a variable parameter
From: azizsaleh@xxxxxxxxx
To: stpetersn@xxxxxxxxxxx
CC: php-general@xxxxxxxxxxxxx

Does the actual filename character count match 111?

On Tue, Sep 29, 2015 at 12:58 PM, Tommy Peterson <stpetersn@xxxxxxxxxxx> wrote:
string(111) and then the correct path/filename



Date: Tue, 29 Sep 2015 12:56:11 -0400

Subject: Re: [PHP] is_readable fails with a variable parameter

From: azizsaleh@xxxxxxxxx

To: stpetersn@xxxxxxxxxxx

CC: php-general@xxxxxxxxxxxxx



var_dump($file_path_name);



What do you get?



On Tue, Sep 29, 2015 at 12:51 PM, Tommy Peterson <stpetersn@xxxxxxxxxxx> wrote:

I am using a PHP API that uses is_readable as a check before a particular function does anything. The problem that I am having is that if I do something like







is_readable($file_path_name);







my code terminates as is_readable says it cannot read the file or there is a permissions issue. But if I go to the file path/name in $file_path_name (echoing it out to make sure) I can see and open the file.







If I edit the same code and do something like







is_readable("/path/to/the/file/filename.zip")







the same code executes just fine.







At first I thought the variable was some how getting over written. But it isn't. It is just somehow the variable is not be interpolated correctly by is_readable like a hard coded path/file name is.







Any thoughts?







This is on Linux. And this is PHP 5.4.43