Web lists-archives.com

Re: [PHP] Capturing part of regex search




On Sun, Aug 23, 2015 at 6:52 PM, Aziz Saleh <azizsaleh@xxxxxxxxx> wrote:

>
>
> On Sun, Aug 23, 2015 at 6:30 PM, Ian Evans <dheianevans@xxxxxxxxx> wrote:
>
>> I've been looking at the regex functions. Either it's a lack of caffeine
>> or
>> it's right in front of my nose, but how do I put part of a regex find into
>> a variable? Plus I suck at regex.
>>
>> e.g.
>>
>> I'm interested in capturing the names of people who are found in text
>> surrounded by the following format:
>>
>> "John Doe":/cr/johndoe/ or "Jane Smith":/cr/janesmith/
>>
>> I'd want to place John Doe or Jane Smith into the variable. The search
>> will
>> always be for "name":/cr/nameurl/
>>
>> What regex and php function would I use? Thanks for any pointers. One of
>> these days I'll master regex.
>>
>
> If the names will always contain double quotes, it should be as easy as:
>
> $var = ' "John Doe":/cr/johndoe/ or "Jane Smith":/cr/janesmith/';
> preg_match_all('/".*"/U', $var, $res);
> print_r($res);
>
> U to make it ungreedy (its greedy by default). If there are other quotes
> in the text, you can add the colon to the expression as well.
>

Thanks. There might be other quotes in the article, so if I include the
colon, it'd be before the /U?