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Re: [glib] malloc and bdwgc




Yes, but the point of my previous email is that the third-party GC_malloc() might eventually call malloc() itself, and by defining a malloc() in my program, GC_malloc() will again call into my malloc() and then GC_malloc() until stack overflow. Do you think this will happen?

Meanwhile since glib provides basic data structures for developers to build their own data structure upon, and developers should be able to decide which allocator their own data structure should use, I still think a GMemVTable should be conceptually necessary. Is there anything that prevents this from being implemented, for example with a g_mem_vtable_init_hook() function? (Are weak symbols possible to be portable? Or if not, missing such feature will still prevent many applications from migrating to the new version of glib.)

Thomas Martitz <kugel@xxxxxxxxxxx>于2016年1月8日周五 下午9:07写道:
Am 08.01.2016 um 12:23 schrieb 张海:
> Thank you very much for pointing me to __libc_* aliases.
>
> However as I was trying to use bdwgc, I didn't figure out whether
> bdwgc will infinite loop as I failed to identify the call to memory
> allocation in its source :(
>
> bdwgc itself has a --enable-redirect-malloc configure option, and by
> greping the source with REDIRECT_MALLOC, I found that to correctly
> redefine malloc and free one need to interfere with redefining dlopen,
> threads and etc, and it seems quite hard to incorporate those lines of
> code into my program. In this case I will need to end up building a
> custom bdwgc with --enable-redirect-malloc.

I'm not sure. You don't have to touch any of the libraries you link if
you implement malloc in the main program. If you define malloc() in a
program, that *all* dynamically linked libraries should use the malloc()
defined in the program. This is because, during dynamic link, unresolved
references are resolved in load-order, and the main program is
conceptually loaded first.

Thus, even the C library should call that, even if it provides malloc
itself, because if global symbols are symbols are defined multiple
times, the first symbol found is used (again, coming from the application).

The following example shows that the application's malloc is used even
for memory allocated internally in the C library (here by asprintf()).
$ cat test.c
#include <stdlib.h>
#include <stdio.h>


extern void *__libc_malloc(size_t);
void *malloc(size_t n)
{
   printf("Sup!?\n");
   return __libc_malloc(n);
}

int main()
{
   char *p = NULL;
   printf("%s\n", (asprintf(&p, "%s\n", "hello world"), p));
}

$ gcc test.c && ./a.out
Sup!?
Sup!?
hello world


PS: This should equally work if you use a third party library to
implement malloc. However, in this case it's important that you link it
first before any other libraries (especially before libc, but I think
gcc does that by default).

Best regards
--
张海
浙江大学 计算机科学与技术
Blog: http://blog.zhanghai.me/
Github: https://github.com/DreaminginCodeZH
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