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Re: [PATCH v4 1/4] Makefile: generate Perl header from template file




Am 29.11.2017 um 16:56 schrieb Dan Jacques:
@@ -1989,6 +1986,15 @@ GIT-PERL-DEFINES: FORCE
  		echo "$$FLAGS" >$@; \
  	    fi
+GIT-PERL-HEADER: $(PERL_HEADER_TEMPLATE) GIT-PERL-DEFINES perl/perl.mak Makefile
+	$(QUIET_GEN)$(RM) $@ && \
+	INSTLIBDIR=`MAKEFLAGS= $(MAKE) -C perl -s --no-print-directory instlibdir` && \
+	INSTLIBDIR_EXTRA='$(PERLLIB_EXTRA_SQ)' && \
+	INSTLIBDIR="$$INSTLIBDIR$${INSTLIBDIR_EXTRA:+:$$INSTLIBDIR_EXTRA}" && \
+	sed -e 's=@@PATHSEP@@=$(pathsep)=g' \

This doesn't work, unfortunately. When $(pathsep) is ';', we get an incomplete sed expression because ';' is also a command separator in the sed language.

+	    -e 's=@@INSTLIBDIR@@='$$INSTLIBDIR'=g' \
+	    $< >$@+ && \
+	mv $@+ $@
.PHONY: gitweb
  gitweb:

-- Hannes