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Providing cygwin1.dll in both 32- and 64-bit versions

I'm cross-compiling on Cygwin64 to 32-bit. Or rather I'm trying to figure out what compiling to 32-bits on a Cygwin64 actually means.

Using 'gcc -m32' causes a lot of "skipping incompatible ..." for a lot of libraries, so obviously ld then looks for the 32-bit libraries in the "wrong" place.

Using 'i686-pc-cygwin-gcc' creates an executable but that is un-runnable in a Cygwin64 environment because the cygwin1.dll is a 64-bit version and not compatible with the produced executable. A cygwin32 DLL needs to be put first in the path to make the executable run.

Is this by design? At least it seems to me that 'gcc -m32' could be taken to mean 'create an executable in the current ABI-environment (cygwin64) which uses a 32-bit architecture'. I'm not sure that makes sense or is even possible, but if it is not, then the question becomes 'how can I make a 32-bit compiled cygwin program run under cygwin64'?

One way to answer that is to say "export PATH=<path_to_32_bit_cygwin1.dll>:$PATH" but that requires installing cygwin32.

I understand that could be the semantics of "cross-compilation" (you could compile for any platform, and can't expect that to run in your host environment), but then I'd like to propose that "-m32" should/could mean compile for host using 32-bit restrictions.

Which part of this is true? Is there a bug with "-m32" or am I just misunderstanding everything?


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